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$解：原式?=\frac {\sqrt {3}}{2}?$

$解：原式?=\frac {3}{x}?$

$解：原式?=\frac {4b2}{a}?$

$解：原式?=\frac {2\sqrt {2}}{3}?$

$解：原式?=\sqrt {\frac {25}{9}}?$

$? =\frac {5}{3}?$

$解：原式?=\frac {7×2}{9}?$

$? =\frac {14}{9}?$

$解：原式?=\frac {x\sqrt {x}}{5y2}?$

$解：原式?=-\sqrt {\frac {54}{3}}?$

$? =-\sqrt {18}?$

$? =-3\sqrt {2}?$

解：原式?$=-\frac {1}{3}\sqrt {\frac {2}{98}}$?

?$ =-\frac {1}{3}×\frac {1}{7}$?

?$ =-\frac {1}{21}$?

$解：原式?=\sqrt {\frac {16}{5}÷\frac {8}{5}}?$

$? =\sqrt {2}?$

解：原式?$=\frac {1}{2}×\sqrt {6ab÷3a}$?

?$ =\frac {1}{2}\sqrt {2b}$?

$?\sqrt {\frac {125}{26}}?$

$?5\sqrt {\frac {5}{26}}?$

$解：?(2)\sqrt {n-\frac {n}{n^2+1}}=n\sqrt {\frac {n}{n^2+1}}?$

$證明：?\sqrt {n-\frac {n}{n^2+1}}=\sqrt {\frac {n(n^2+1)-n}{n^2+1}}=\sqrt {\frac {n^3+n-n}{n^2+1}}?$

$?=\sqrt {\frac {n^3}{n^2+1}}=n \sqrt {\frac {n}{n^2+1}}?$

解：設(shè)下底長為?$x$?

?$(2+x)×\sqrt {2}×\frac {1}{2}=\sqrt {50}$?

?$ x=8$?

∴梯形的下底長為?$8$?

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