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電子課本網(wǎng) 第113頁

第113頁

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C
$解:原式?=\sqrt {100×3}?$
$? =10\sqrt {3}?$
$解:原式?=\sqrt {5×3×4×5}?$
$? =10\sqrt {3}?$
$解:原式?=2b\sqrt {a}?$
$解:原式?=\sqrt {a2(a+2)}?$
$?=a\sqrt {a+2}?$
$解:原式?=-3ab\sqrt ?$
$解:原式?=\sqrt {(2n-2)2}?$
$? =2n-2?$
$解:?(1)?原式?=\sqrt {10×\frac {2}{5}}=\sqrt {4}=2?$
$?(2)?原式?=-\sqrt {\frac {2}{3}×48}=-\sqrt {32}=-4\sqrt {2}?$
$(3)?原式?=\sqrt {ab×\frac {b3}{a}}=\sqrt {b^4}=b2?$
$?(4)?原式?=a2×\frac {1}{a}×\sqrt {2b^5×8b}=a\sqrt {16b^6}=4ab3?$
$解:?(1)?原式?=\sqrt {3ab×a}=a\sqrt {3b}?$
$將?a=\frac {1}{2},??b=3?代入得原式?=\frac {1}{2}×\sqrt {3×3}=\frac {3}{2}?$
$?(2)?原式?=\sqrt {ab3×2b}=b2\sqrt {2a}?$
$將?a=\frac {1}{2},??b=3?代入原式?=32×\sqrt {2×\frac {1}{2}}=9?$
$解:?V=2\sqrt {6}×\sqrt {3}×\sqrt {2}=2\sqrt {6×3×2}=12(\mathrm {cm}3)?$
$解:?(1)2\sqrt {12}=\sqrt {2^2×12}=\sqrt {48}?$
$∵?48>27?$
$∴?2\sqrt {12}>\sqrt {27}?$
$?(2)2\sqrt {3}=\sqrt {2^2×3}=\sqrt {12},??3\sqrt {2}=\sqrt {3^2×2}=\sqrt {18}?$
$∵?12<18?$
$∴?2\sqrt {3}<3\sqrt {2}?$
$解:?\sqrt {3}×\sqrt {\frac {1}{3}}=1?$