亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区

電子課本網(wǎng) 第98頁(yè)

第98頁(yè)

信息發(fā)布者:
$?解:原式 ={\sqrt {4{x}^{2}(3y+6{y}^{3})}}$
$={\sqrt {4{x}^{2}}}·{\sqrt {3y+6{y}^{3}}}$
$=2x{\sqrt {3y+6{y}^{3}}}$
$={({\sqrt {3}}×{\sqrt {5}})}×({\sqrt {5}}×{\sqrt {7}})$
$=({\sqrt {5}×{\sqrt {5}}})×({\sqrt {3}×{\sqrt {7}}})$
$=5{\sqrt {21}}$
$=({\sqrt {3}×{\sqrt {6}}})×2{\sqrt {6}}$
$={\sqrt {3}×({\sqrt {6}}}×2{\sqrt {6}})$
$=12{\sqrt {3}}$
$={\sqrt {54×{\frac {2} {3}}}}$
$={\sqrt {36}}$
$=6$
$={\sqrt {56×{\frac {1} {7}}}}$
$={\sqrt {8}}$
$=2{\sqrt {2}}$
$={\sqrt {{a·a}^{3}^{2}}}$
$={\sqrt {{a}^{4}^{2}}}$
$={a}^{2}b$
$={\sqrt {\frac {a} {2}·4{a}^{2}}}$
$={\sqrt {2{a}^{3}}}$
$=a{\sqrt {2a}}$
$解:{\sqrt {{10}^{2}+{20}^{2}}}=10{\sqrt {5}}(cm)$
$答:斜邊的長(zhǎng)為10\sqrt {5}cm。$