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電子課本網(wǎng) › 第138頁

第138頁

信息發(fā)布者：

$解：原式?=\sqrt {56÷7}?$

$? =\sqrt {8}?$

$? =2\sqrt {2}$

$解：原式?=\sqrt {30}×\sqrt {6}÷\sqrt {10}?$

$? =\sqrt {30×6÷10}?$

$? =\sqrt {18}?$

$? =3\sqrt {2}?$

$解：原式=3\sqrt {2}-2\sqrt {3}-2\sqrt {2}?$

$?=\sqrt {2}-2\sqrt {3}$

$解：原式?=2\sqrt {6}-\frac {\sqrt {2}}{2}+\frac {2\sqrt {6}}{3}-\frac {\sqrt {2}}{4}-\sqrt {6}?$

$? =\frac {5\sqrt {6}}{3}-\frac {3\sqrt {2}}{4}$

$解：原式?=π-2+6-π?$

$? =4?$

$解：原式?=\sqrt {2}+1+3-3\sqrt {2}+2\sqrt {2}?$

$? =4$

$解：原式?=\frac {\sqrt {x-2}}{x-2}×\sqrt {x(x-2)}?$

$? =\sqrt {x}?$

$ 當(dāng)?x=4?時(shí)，原式?=\sqrt {4}=2?$

$解：由題意可得：?a＜0＜b?$

$ 所以原式?=-a-b+a-b=-2b$

$解：? (a+1)(b- 1)= ab+b- a- 1?$

$當(dāng)?a- b=5\sqrt {2}- 1，??ab=\sqrt {2}?時(shí)，$

$原式?=\sqrt {2}+1-5\sqrt {2}- 1=-4\sqrt {2}$

$解：原式?=a2-2ab+b2+ab?$

$?=(a-b)2+ab?$

$當(dāng)?a=\sqrt {3}+\sqrt {2}，??ab=\sqrt {3}-\sqrt {2}?$

$所以?a-b=2\sqrt {2}，??ab=1?$

$所以原式?=(2\sqrt {2})2+1?$

$? =9$