電子課本網(wǎng) › 第111頁

第111頁

信息發(fā)布者：

A

B

D

$解?：(1)2\sqrt {12}=4\sqrt {3}，\sqrt {27}=3\sqrt {3}，?是同類二次根式$

$?(2)\sqrt {50}=5\sqrt {2}，3\sqrt {8}=6\sqrt {2}，?是同類二次根式$

$?(3)2\sqrt {1\frac {1}{2}}=\sqrt {6}，2\sqrt {48}=8\sqrt {3}，?不是同類二次根式.$

$解?：=(3\sqrt {5}+\sqrt {5})-(\sqrt {2}+4\sqrt {2})?$

$? =4\sqrt {5}-5\sqrt {2}?$

$解:=5\sqrt {3}-15\sqrt {3}-3\sqrt {3}?$

$? =-13\sqrt {3}?$

$解?：=6\sqrt {2}+3\sqrt {2}-\frac {3\sqrt {2}}{2}?$

$? =\frac {15\sqrt {2}}{2}?$

$解：?=4\sqrt {2}-4\sqrt {3}-\frac {\sqrt {3}}{3}-3\sqrt {2}?$

$? =\sqrt {2}-\frac {13\sqrt {3}}{3}?$

$解?：=4\sqrt {3}-\frac {4\sqrt {3}}{9}+12\sqrt {3}?$

$? =\frac {140\sqrt {3}}{9}?$

$解:?=\frac {\sqrt {2}}{2}-\frac {2\sqrt {3}}{3}-\frac {\sqrt {2}}{4}+5\sqrt {3}?$

$? =\frac {\sqrt {2}}{4}+\frac {13\sqrt {3}}{3}?$

亚洲激情+欧美激情,无码任你躁久久久久久,我的极品美女老婆,性欧美牲交在线视频,亚洲av高清在线一区二区三区