$解:因?yàn)?0<x<1?$
$所以?\frac {1}{x}>x?$
$原式?=\sqrt {x2+\frac {1}{x2}-2+4}-\sqrt {x2+\frac {1}{x2}+2-4}?$
$?=\sqrt {x2+\frac {1}{x2}+2}-\sqrt {x2+\frac {1}{x2}-2}?$
$?=\sqrt {(x+\frac {1}{x})2}-\sqrt {(x-\frac {1}{x})2}?$
$?=|x+\frac {1}{x}|-|x-\frac {1}{x}|?$
$?=x+\frac {1}{x}-(\frac {1}{x}-x)?$
$?=2x?$