?$解:原式??=\frac {2(x-3)}{x2-9}-\frac {2(x+3)}{x2-9}+\frac {2x+18}{x2-9}??$?
?$?? =\frac {2x-6-2x-6+2x+18}{x2-9}??$?
?$?? =\frac {2}{x-3}??$?
$ 因為分式的值為整數(shù)$
?$ 所以??x-3=±1,????±2??$?
$ 因為分式有意義$
?$ 所以??x≠3??且??x≠-3??$?
?$ 所以??x=2,4,1,5??$?
?$ 和為??12$?