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電子課本網(wǎng) 第70頁

第70頁

信息發(fā)布者:
B
$解:原式??=\frac {5x-2y}{3x+20y}??$
$解:原式??=\frac {12a+3b}{16a-24b}??$
$解??:\frac {2}{3a2}=\frac {4b2}{6a2b2}??$
$??\frac {1}{6ab2}=\frac {a}{6a2b2}??$
$解??:\frac {a}{2b}=\frac {6a3}{12a2b}??$
$??\frac {3a2}=\frac {4b2}{12a2b}??$
$??\frac {c}{4ab}=\frac {3ac}{12a2b}??$
$解??:\frac {x-1}{-2x2}=-\frac {6x(x-1)}{12x3}??$
$??\frac {4}{3x}=\frac {16x2}{12x3}??$
$??\frac {x+1}{4x3}=\frac {3x+3}{12x3}??$
$解??:\frac {5}{x-y}=\frac {5(x-y)}{(x-y)2}??$
$??\frac {2}{(y-x)2}=\frac {2}{(x-y)2}??$
$解:分式可寫為??\frac {5-4x}{x2-x+3}??$
$解:分式可寫為??\frac {-3-x}{(x-1)(x-2)}??$