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電子課本網(wǎng) › 第72頁

第72頁

信息發(fā)布者：

$??\sqrt 2??$

$??1-\frac {\sqrt 3}2??$

$??\sqrt 3+\frac {1}{2}??$

②③④

71cm

$解：原式??=2×\frac 12+3×\frac 12-4×1??$

$?? =1+\frac 32-4??$

$?? =-\frac 32??$

$解：原式??=\frac {(\frac {\sqrt 3}2)^2}{1+\frac 12}+(\sqrt 3)^2??$

$?? =\frac {\frac 34}{\frac 32}+3??$

$?? =\frac 12+3??$

$?? =\frac 72??$

$解：原式?=(\frac {\sqrt 3}2)^2+(\frac 12)^2-1?$

$?=\frac 34+\frac 14-1?$

$? =0?$

$解：??sin α=\frac {\sqrt 3}2??$

$∵??sin 60°=\frac {\sqrt 3}2??$

$∴??α=60°??$

$解：??tan (α+10°)=\frac {\sqrt 3}3??$

$∵??tan 30°=\frac {\sqrt 3}3??$

$∴??α+10°=30°，????α=20°??$

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