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第62頁

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$\frac{2}{5}$

$\frac{1}{3}$

1

$\frac{2}{9}$

$\frac{12}{35}$

$\frac{1}{3}$

$?\begin{aligned} 解： x&=\frac 12-\frac 14\\x&=\frac 14\end{aligned}?$

$?\begin{aligned} 解： x&=1-\frac 35\\x&=\frac 25\end{aligned}?$

$?\begin{aligned} 解： x&=\frac 56+\frac 12\\x&=\frac 43\end{aligned}?$

$?\begin{aligned} 解： x&=\frac 25+\frac 47\\x&=\frac {34}{35}\end{aligned}?$

?$ =\frac {7}{8}+\frac {1}{8}+\frac {4}{7}$?

?$=1+\frac {4}{7}$?

?$=\frac {11}{7}$?

?$ =\frac {9}{5}-(\frac {2}{7}+\frac {5}{7})$?

?$=\frac {9}{5}-1$?

?$=\frac {4}{5}$?

?$ =(\frac {5}{9}+\frac {4}{9})-(\frac {3}{8}+\frac {3}{8})$?

?$=1-\frac {6}{8}$?

?$=\frac {1}{4}$?

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