$解:?(1)?∵?GF//AB,??GE//AC?$
$∴?∠B=∠GFE,??∠C=∠GEF?$
$∴?△ABC∽△GFE?$
$∵?AG=2GD?$
$∴?AD=3GD?$
$∵?GF//AB?$
$∴?\frac {AB}{GF}=\frac {AD}{GD}=3?$
$∴?△ABC?與?△GFE?的相似比為?3?$
$∴?△ABC?的周長?=5.5×3=16.5?$
$?(2)S_{△ABC}=\frac 12×6×5=15?$
$?△ABC?與?△GFE?的面積比為?9:??1?$
$∴?S_{△GFE}=\frac {15}{9}=\frac {5}{3}?$