$解:設(shè)?A(x_{1},??y)、??B(x_{2},??y)?$
$由題意可得?\begin{cases}{x_{1}+x_{2}=0}\\{x_{2}-x_{1}=1}\end{cases},?解得?\begin{cases}{x_{1}=-\dfrac 12}\\{x_{2}=\dfrac 12}\end{cases}?$
$?y=-2×(\frac 12)^2=-\frac 12?$
$∴?A(-\frac 12,??-\frac 12)、??B(\frac 12,??-\frac 12)?$