$解：???(1) ???出現(xiàn)和為???7???的概率是???0.33???$
$???(2)???列表如下$
$一共有???12???種可能的結(jié)果$
$由???(1)???知，出現(xiàn)和為???7???的概率約為???0.33???$
$∴和為???7???出現(xiàn)的次數(shù)為???0.33×12=3.96≈4???$
$若???2+x=7，???則???x=5，???此時???P(???和為???7)=\frac {1}{3} ≈0.33，???符合題意$
$若???3+x=7，???則???x=4，???不符合題意$
$若???4+x=7，???則???x=3，???不符合題意$
$∴???x=5???$
