$解：過(guò)點(diǎn)?C?作?CE⊥AB?于?E，?過(guò)點(diǎn)?B?作?BF⊥CD?于?F?$
$∵在?Rt△BFD?中，?∠DBF=30°?$
$∴?sin∠DBF= \frac {DF}{BD}=\frac {1}{2}?$
$?cos∠DBF= \frac {BF}{BD}=\frac {\sqrt{3}}{2}?$
$∵?BD=6?$
$∴?DF=3，??BF= 3\sqrt{3}?$
$∵?AB//CD，??CE⊥AB，??BF⊥CD?$
$∴四邊形?BFCE?為矩形$
$∴?BF=CE= 3\sqrt{3}，??CF=BE=CD-DF=1?$
$∵在?Rt△ACE?中，?∠ACE=45°?$
$∴?AE=CE= 3\sqrt{3}?$
$∴?AB=AE+BE=3 \sqrt{3}+1?$
$即鐵塔?AB?的高為?(3 \sqrt{3}+1)?米$
