解:?$(1)A+3B=-x-2y-1+3(\frac {1}{2}x+y+1)$?
?$=-x-2y-1+\frac {3}{2}x+3y+3$?
?$=\frac {1}{2}x+y+2$?;
?$(2)$?將?$x+2y=6$?代入,得
?$A+3B=\frac {1}{2}(x+2y)+2=3+2=5$?
?$(3)$?即?$A+mB=-x-2y-1+m(\frac {1}{2}x+y+1)$?
?$=(\frac {m}{2}-1)x+(m-2)y+m-1$?的值與?$y$?無關(guān)
則?$m-2=0$?
得?$m=2.$?