?$ 解:(\frac {1}{6}-\frac {2}{7}+\frac {2}{3}-\frac {3}{14})÷(-\frac {1}{42})$?
?$=(\frac {1}{6}-\frac {2}{7}+\frac {2}{3}-\frac {3}{14})×(-42)$?
?$=(-7)+12-28+9$?
?$=-14所以(-\frac {1}{42})÷(\frac {1}{6}-\frac {2}{7}+\frac {2}{3}-\frac {3}{14})=-\frac {1}{14}$?