證明:∵?$AC$?平分?$∠BCD$?,?$BD$?平分?$∠ABC$?,
∴?$∠DBC=\frac {1}{2}∠ABC$?,?$∠ACB=\frac {1}{2}∠DCB$?,
∵?$∠ABC=∠DCB$?,
∴?$∠ACB=∠DBC$?,
在?$△ABC$?與?$△DCB$?中
?$\begin {cases}{∠A B C=∠D C B}\\{ B C=C B}\\{∠A C B=∠D B C}\end {cases}$?
∴?$△ABC≌△DCB(\mathrm {ASA})$?
∴?$AB=CD.$?