解:?$(1)\ \mathrm {A} B=\sqrt {(-3-2)^2+(-8-4)^2}=13$?
?$(2)\ \mathrm {A} B=4-(-1)=5$?
?$(3) \triangle D E F $?是等腰三角形?$,$?
理由如下:
?$D E=\sqrt {(-2-1)^2+(2-6)^2}=5,$?
?$E F=\sqrt {(4+2)^2+(2-2)^2}=6,$?
?$D F=\sqrt {(4-1)^2+(2-6)^2}=5,$?
則?$ D E=D F,$?
∴?$\triangle D E F $?是等腰三角形?$.$?