?$解：設(shè)需要消耗\mathrm {MgCl}_{2}的質(zhì)量是x。 $?
?$\mathrm{MgCl}_{2}(熔融)\xlongequal[]{通電}\mathrm{Mg}_{ }＋\mathrm{Cl}_{2}↑$?
?$\mathrm{\frac {95 }{x }=\frac {24 }{48t }~~~~~解得 x =190t }$
?
?$答：應(yīng)用此法制備48\mathrm {t}鎂，至少需要消耗\mathrm {MgCl}_{2}的質(zhì)量是190\mathrm {t}。$?
