解：∵?$a$?，?$b$?互為倒數(shù)，?$c$?，?$d$?互為相反數(shù)，?$|m|=3$?
∴?$ab=1$?，?$c+d=0$?，?$m=±3$?
∴當(dāng)?$m=3$?時，?$\frac {ab}{3}+m +\frac {c+d}{4} =\frac {1}{3}+3+\frac {0}{4}=\frac {10}{3} $?
當(dāng)?$m=-3$?時，?$\frac {ab}{3}+m +\frac {c+d}{4} =\frac {1}{3}+(-3)+\frac {0}{4} =-\frac {8}{3} $?
由上可得，?$\frac {ab}{3}+m +\frac {c+d}{4}$?的值是?$\frac {10}{3}$?或?$-\frac {8}{3}$?
