解:?$(1)$?當(dāng)?$x=2$?時(shí),陰影部分的面積為
?$2×2+4×3-\frac {1}{2}×2×2-\frac {1}{2}×3×(2+4)-\frac {1}{2}×4×(3-2)=3$?
?$(2)$?陰影部分的面積為
?$x2+4×3-\frac {1}{2}x2-\frac {1}{2}×3(x+4)-\frac {1}{2}×4(3-x)$?
?$=x2+12-\frac {1}{2}x2-\frac {3}{2}x-6-6+2x$?
?$=\frac {1}{2}x2+\frac {1}{2}x$?