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電子課本網(wǎng) 第61頁

第61頁

信息發(fā)布者:
±3
10
120
$ 解:原式=(40+\frac{1}{3} ×(\frac{1}{3}-40) $
$~~~~~~~~~~~~~~~~~=(\frac{1}{3})2 -402 $
$~~~~~~~~~~~~~~~~~=\frac{1}{9}-1600 $
$~~~~~~~~~~~~~~~~~= -1599\frac{8}{9} $
$ \begin{aligned}解:原式&=20222-(2022-1)×(2022+1) \\ &=20222-20222+1 \\ &=1. \\ \end{aligned}$
$解:原式=\frac{1}{5}×7.352-\frac{1}{5}×25×1.072$
$~~~~~~~~~~~~~~~~~=\frac{1}{5}×(7.352-52×1.072)$
$~~~~~~~~~~~~~~~~~= \frac{1}{5}×(7.352-5.352)$
$~~~~~~~~~~~~~~~~~=\frac{1}{5}×(7.35-5.35)×(7.35+5.35)$
$~~~~~~~~~~~~~~~~~=\frac{1}{5}×2×12.7$
$~~~~~~~~~~~~~~~~~=5.08.$
(更多請點擊查看作業(yè)精靈詳解)
(更多請點擊查看作業(yè)精靈詳解)
6
1
$ \begin{aligned}解:原式&=(3-1)×(3+1)×(3^2+1)×(3^4+1)×(3^8+1)+1 \\ &=(3^2-1)×(3^2+1)×(3^4+1)×(3^8+1)+1 \\ &=(3^4-1)×(3^4+1)×(3^8+1)+1 \\ &=(3^8-1)×(3^8+1)+1 \\ &=3^{16} \\ \end{aligned}$
$解:原式=(1-\frac{1}{2})×(1+\frac{1}{2})×(1-\frac{1}{3})×(1+\frac{1}{3})×(1- \frac{1}{4})×(1+\frac{1}{4})×···×(1-\frac{1}{10})×(1+\frac{1}{10})$
$=\frac{1}{2}×\frac{3}{2}×\frac{2}{3}×\frac{4}{3}×\frac{3}{4}×\frac{5}{4}×···×\frac{9}{10}×\frac{11}{10}$
$=\frac{1}{2}×\frac{11}{10}$
$=\frac{11}{20}$
$解:原式=(100+99)×(100-99)+(98+97)×(98-97)+···+(4+3)×(4-3)+(2+1)×(2-1)$
$=100+99+98+97+···+4+3+2+1$
$=5050.$