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電子課本網(wǎng) 第136頁

第136頁

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$\frac{4\sqrt {3} }{3}$
$\frac{\sqrt {6} }{2}$
$\frac{5\sqrt {6} }{4}$
$4\sqrt {6}\ $
$\frac{8\sqrt {6} }{3}$
$解:原式=\frac{2\sqrt{3x}}{3}$
$解:原式=\frac{\sqrt {6ab}}{4a2}$
$ \begin{aligned}解:原式&= \sqrt{\frac{4}{3}×\frac {3}{7}×\frac {5}{7}} \\ &=\sqrt{\frac{20}{72}} \\ &=\frac{2\sqrt {5} }{7}. \\ \end{aligned}$
$ \begin{aligned}解:原式&= \sqrt{\frac{a}·\frac{1}{ab}·\frac{a^{3} }} \\ &= \sqrt{\frac{a}} \\ &=\frac{\sqrt {ab} }. \\ \end{aligned}$
$ \begin{aligned}解:原式&=\sqrt {18}÷ \sqrt{84×\frac {2}{7}} \\ &=\sqrt {18} ÷\sqrt {24}\ \\ &= \sqrt{\frac{18}{24}}= \sqrt{\frac{3}{4}} =\frac{\sqrt {3} }{2}. \\ \end{aligned}$
$ \begin{aligned}解:原式&=8x2 \sqrt{xy}÷\sqrt {\frac {x^{3} }{9y}}×(-\sqrt {\frac {y^{2} }{x}} ) \\ &=-8x2 \sqrt{xy·\frac{9y}{x^{3} }·\frac {y^{2} }{x}} \\ &=-8x2\sqrt {\frac {9y^{4} }{x^{3} }}\ \\ &=-8x2·\frac{3y2\sqrt{x}}{x2} \\ &=-24y2\sqrt{x}. \\ \end{aligned}$
$解:原式=\frac{\sqrt {3} }{6}$
$解:原式=\frac{3\sqrt {5} }{5}$