解：?$(1)$?猜想，?$\sqrt{2011}-\sqrt{2010}＞\sqrt{2012}-\sqrt{2011}$?
?$\sqrt{2011}-\sqrt{2010}=\frac {(\sqrt{2011}-\sqrt{2010})(\sqrt{2011}+\sqrt{2010})}{\sqrt{2011}+\sqrt{2010}}=\frac 1{\sqrt{2011}+\sqrt{2010}}$?
?$\sqrt{2012}-\sqrt{2011}=\frac {(\sqrt{2012}-\sqrt{2011})(\sqrt{2012}+\sqrt{2011})}{\sqrt{2012}+\sqrt{2011}}=\frac 1{\sqrt{2012}+\sqrt{2011}}$?
?$∵\(yùn)sqrt{2011}+\sqrt{2010}＜\sqrt{2012}+\sqrt{2011}$?
?$∴\frac 1{\sqrt{2011}+\sqrt{2010}}＞\frac 1{\sqrt{2012}+\sqrt{2011}}，$?即?$\sqrt{2011}-\sqrt{2010}＞\sqrt{2012}-\sqrt{2011}$?
?$(2)$?由?$(1)$?可得
原式??$=\sqrt{2}-1+\sqrt{3}-\sqrt{2}+....+10-\sqrt{99}$??
?$=10-1$?
?$=9$?
