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電子課本網(wǎng) 第105頁

第105頁

信息發(fā)布者:
解:原式?$=\frac {\sqrt{2y}}{3x\sqrt{2x}}$?
?$=\frac {\sqrt{xy}}{3x^2}$?
?$解:原式=-\sqrt{(a-1)^2×(-\frac 1{a-1})}$?
                ?$=-\sqrt{1-a}$?
解:原式?$=\frac {\sqrt{11}×\sqrt{3}}{\sqrt{3}×\sqrt{3}}$?
?$=\frac {\sqrt{33}}{3}$?
解:原式?$=\frac {\sqrt{14}×\sqrt{6}}{\sqrt{6}×\sqrt{6}}$?
?$=\frac {\sqrt{21}}{3}$?
解:原式?$=\frac {3\sqrt{y}}{x\sqrt{y}×\sqrt{y}}$?
?$=\frac {3\sqrt{y}}{xy}$?
解:?$(1)\frac {1}{1+\sqrt{2}}=\frac {1-\sqrt{2}}{(1+\sqrt{2})(1-\sqrt{2})}=-(1-\sqrt{2})=-1+\sqrt{2}$?
?$(2)\frac 1{\sqrt{n}+\sqrt{n+1}}=-\sqrt{n}+\sqrt{n+1}$?
?$(3)$?原式?$=(-1+\sqrt{2}-\sqrt{2}+\sqrt{3}-\sqrt{3}+\sqrt{4}+...-\sqrt{2014}+\sqrt{2015})×(1+\sqrt{2015})$?
?$ =(-1+\sqrt{2015})(1+\sqrt{2015})$?
?$ =2015-1$?
?$ =2014$?