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電子課本網(wǎng) 第146頁

第146頁

信息發(fā)布者:
解:原式?$=a+2\sqrt {a}-a$?
?$ =2\sqrt {a}$?
解:原式?$=\sqrt {4{(a+1)}^2}$?
?$ =2(a+1)$?
解:原式?$=xy(x-y)$?
∵?$x=2-\sqrt {3},$??$y=2+\sqrt {3}$?
∴?$xy=1,$??$x-y=-2\sqrt {3}$?
∴原式?$=1×(-2\sqrt {3})=-2\sqrt {3}$?
解:原式?$={(a-1)}^2+(a-1)+2={(a-1+1)}^2+1=a^2+1$?
∵?$a=\sqrt {2}$?
∴原式?$={(\sqrt {2})}^2+1=3$?
解:?$25\sqrt {2}×16\sqrt {3}÷10\sqrt {15}=8\sqrt {10}(\mathrm {cm})$?
答:乙的寬為?$8\sqrt {10}\mathrm {cm}。$?
解:?$\frac 1 {\sqrt {n+1}+\sqrt {n}}=\sqrt {n+1}-\sqrt {n}$?
解:原式?$=(\sqrt {2}-1)+(\sqrt {3}-\sqrt {2})+···+(\sqrt {10}-\sqrt {9})$?
?$ =\sqrt {10}-1$?