解:??$a(\frac 1b+\frac 1c)+b(\frac 1c+\frac 1a)+c(\frac 1a+\frac 1b)=\frac ab+\frac ac+\frac bc+\frac ba+\frac ca+\frac cb$??
??$ =\frac {b+c}a+\frac {a+c}b+\frac {a+b}c=-1-1-1=-3$??
??$ ∴a(\frac 1b+\frac 1c)+b(\frac 1c+\frac 1a)+c(\frac 1a+\frac 1b)+3=0$??