電子課本網(wǎng) › 第109頁

第109頁

信息發(fā)布者：

$? \frac {\sqrt {3}}{3}?$

$ \sqrt {6}$

$? \frac {\sqrt {2}}{2}?$

$ \frac{\sqrt{6}}{2}$

$? \frac {\sqrt {6}}{3}?$

$? \frac {\sqrt {6}}{6}?$

$解：矩形的另外一條邊長(zhǎng)為?2\sqrt {6}÷\sqrt {2}=2\sqrt {3}\mathrm {cm}?$

$ 對(duì)角線的長(zhǎng)為?\sqrt {(\sqrt {2})2+(2\sqrt {3})2}=\sqrt {14}\mathrm {cm}?$

$解：?(1)?原式?=\sqrt {9m^5n^4÷25m^4n^3}?$

$? =\frac {3}{5}\sqrt {mn}?$

$解：?(2)?原式?=\sqrt {4ab3÷\frac {36a}{b3}×(-\frac {\sqrt {9a3b}}{4})}?$

$? =-\frac {ab3\sqrt {ab}}{2}?$

$解：?(3)?原式?=\frac {\sqrt {2}-1}{(\sqrt {2}+1)(\sqrt {2}-1)}?$

$? =\sqrt {2}-1?$

$? (4)?原式?=\frac {\sqrt {3}+2}{(\sqrt {3}-2)(\sqrt {3}+2)}?$

$? =-\sqrt {3}-2?$

$? (5)?原式?={[(\sqrt {3}-2)×(\sqrt {3}+2)]}^{2021}×(\sqrt {3}+2)?$

$? =-\sqrt {3}-2?$

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