解:因為?$0＜x＜1$?
所以?$\frac {1}{x}＞x$?
原式?$=\sqrt {x2+\frac {1}{x2}-2+4}-\sqrt {x2+\frac {1}{x2}+2-4}$?
?$=\sqrt {x2+\frac {1}{x2}+2}-\sqrt {x2+\frac {1}{x2}-2}$?
?$=\sqrt {(x+\frac {1}{x})2}-\sqrt {(x-\frac {1}{x})2}$?
?$=|x+\frac {1}{x}|-|x-\frac {1}{x}|$?
?$=x+\frac {1}{x}-(\frac {1}{x}-x)$?
?$=2x$?
