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解:因?yàn)?$\frac {1}{x}-\frac {1}{y}=3$?
?$ \frac {1}{x}-\frac {1}{y}=\frac {y-x}{xy}=3$?
所以?$y-x=3xy$?
原式?$=\frac {x-(y-x)-y}{2x+y-x-2y}$?
?$ =\frac {2(x-y)}{x-y}$?
?$ =2$?
D
A
解:原式?$=\frac {a-b}{a-b}×\frac {ab}{a-b}$?
?$ =\frac {ab}{a-b}$?
解:原式?$=\frac {x(x+2)-x(x-2)}{(x-2)(x+2)}×\frac {2-x}{4x}$?
?$ =\frac {4x}{(x+2)(x-2)}×\frac {2-x}{4x}$?
?$ =-\frac {1}{x+2}$?
解:原式?$=1-\frac {a-b}{a+2b}×\frac {(a+2b)2}{(a-b)(a+b)}$?
?$ =1-\frac {a+2b}{a+b}$?
?$ =-\frac {a+b}$?
解:原式?$=\frac {a2-b2+2b2}{a-b}$?
?$ =\frac {a2+b2}{a-b}$?
解:原式?$=\frac {(x-y)2+4xy}{x-y}×\frac {(x+y)2-4xy}{x+y}$?
?$ =\frac {(x+y)2}{x-y}×\frac {(x-y)2}{x+y}$?
?$ =(x+y)(x-y)$?
?$ =x2-y2$
?
解:原式?$=\frac {m+2-(m-2)}{(m+2)(m-2)}$?
?$+\frac {2(m-1)-2(m+1)}{(m+1)(m-1)}$?
?$ =\frac {4}{(m+2)(m-2)}-\frac {4}{(m+1)(m-1)}$?
?$ =\frac {12}{(m+2)(m-2)(m+1)(m-1)}$?
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