解:原式?$= 2×\frac 12×(1+\frac 12)(1+\frac 14)×(1+\frac 1{16})$?
?$ = 2×(1-\frac 12)(1+\frac 12)(1+\frac 14)(1+\frac 1{16})$?
?$ = 2×(1-\frac 14)(1+\frac 14)(1+\frac 1{16})$?
?$ = 2×(1-\frac 1{16})(1+\frac 1{16})$?
?$ = 2×\frac 1{162}$?
?$ = 2×\frac {255}{256}$?
?$ = \frac {255}{128}$?