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電子課本網(wǎng) 第99頁

第99頁

信息發(fā)布者:
$?={\sqrt {\frac {90} {10}}}$
$={\sqrt {9}}$
$=3$
$?={\sqrt {\frac {96} {6}}}$
$=\sqrt {16}$
$=4$
$={\sqrt {\frac {75} {15}}}$
$={\sqrt {5}}$
$={\sqrt {\frac {450} {10}}}$
$={\sqrt {45}}$
$=3{\sqrt {5}}$
$={\sqrt {{\frac {10} {3}}÷{\frac {5} {3}}}}$
$={\sqrt {2}}$
$={\sqrt {75÷15}}$
$={\sqrt {5}}$
$解:{\sqrt {\frac {12} {49}}}={\frac {\sqrt {12}} {\sqrt {49}}}={\frac {2{\sqrt {3}}} {7}}$
?$解:{\sqrt {5{\frac {4} {9}}}}={\sqrt {\frac {49} {9}}}={\frac {\sqrt {49}} {\sqrt {9}}}={\frac {7} {3}}$?
?$解:{\sqrt {\frac {3^2} {4{a}^2}}}={\frac {\sqrt {3^2}} {\sqrt {4{a}^2}}}={\frac {\sqrt {3}b} {2a}}$?
$解:{\sqrt {\frac {2b} {9{a}^{2}}}}={\frac {\sqrt {2b}} {\sqrt {9{a}^{2}}}}={\frac {\sqrt {2b}} {3a}}$