?$解:(1)因為2×{8}^{x}×{16}^{x}=2×{2}^{3x}×{2}^{4x}={2}^{1+3x+4x}={2}^{1+7x},$?
?$又因為2×{8}^{x}×{16}^{x}=2^{22},$?
?$所以1+7x=22,$?
?$解得,x=3$?
?$(2)因為{({27}^{x})}^{2}={({3}^{3x})}^{2}={3}^{6x},$?
?$又因為{({27}^{x})}^{2}={3}^{8},$?
?$所以6x=8,$?
?$解得,x=\frac 4 3$?