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電子課本網(wǎng) 第76頁

第76頁

信息發(fā)布者:
$ 解:(1)V_水=\frac {m_水}{ρ_水}=\frac { 9\ \text {kg}}{1.0×10^{3}\ \text {kg/m}^3}= 0.009\ \text {m}^3$
$ (2)V_冰=\frac {m_水}{ρ_冰}=\frac {9\ \text {kg}}{0.9×10^{3}\ \text {kg/m}^3}= 0.01\ \text {m}^3$
$ (3)水結(jié)冰后,體積變大,可能會脹破水管$
$ 解:V_鋁=\frac {m_鋁}{ρ_鋁}=\frac {27\ \text {g}}{2.7\ \text {g/cm}^3}=10\ \text {cm}^3$
$ m_液=m_總-m_鋁=43\ \text {g}- 27\ \text {g}=16\ \text {g}$
$ V_液=V_球-V_鋁=30\ \text {cm}^3-10\ \text {cm}^3=20\ \text {cm}^3$
$ ρ_液=\frac {m_液 }{V_液}=\frac {16\ \text {g}}{ 20\ \text {cm}^3}=0.8\ \text {g/cm}^3$