$ 解:V_鋁=\frac {m_鋁}{ρ_鋁}=\frac {27\ \text {g}}{2.7\ \text {g/cm}^3}=10\ \text {cm}^3$
$ m_液=m_總-m_鋁=43\ \text {g}- 27\ \text {g}=16\ \text {g}$
$ V_液=V_球-V_鋁=30\ \text {cm}^3-10\ \text {cm}^3=20\ \text {cm}^3$
$ ρ_液=\frac {m_液 }{V_液}=\frac {16\ \text {g}}{ 20\ \text {cm}^3}=0.8\ \text {g/cm}^3$