$\frac{1}{2}=\dfrac{2}{4},\dfrac{3}{4}\gt \dfrac{2}{4},所以\dfrac{3}{4}\gt \dfrac{1}{2}$
$6\gt 2,所以\frac{1}{6}\lt \dfrac{1}{2}$
$\frac{1}{2}=\dfrac{4}{8},\dfrac{3}{8}\lt \dfrac{4}{8},所以\dfrac{3}{8}\lt \dfrac{1}{2}$
$\dfrac{1}{2}=\dfrac{5}{10},\dfrac{5}{9}\gt \dfrac{5}{10},所以\dfrac{5}{9}\gt \dfrac{1}{2}$
$\dfrac{1}{2}=\dfrac{6}{12},\dfrac{6}{7}\gt \dfrac{6}{12},所以\dfrac{6}{7}\gt \dfrac{1}{2}$
$\dfrac{1}{2}=\dfrac{6}{12},\dfrac{6}{11}\gt \dfrac{6}{12},所以\dfrac{6}{11}\gt \dfrac{1}{2}$
$\dfrac{1}{2}=\dfrac{7}{14},\frac{7}{13}\gt \dfrac{7}{14},所以\frac{7}{13}\gt \dfrac{1}{2}$
$比\frac{1}{2}小的分數(shù):\dfrac{1}{6},\dfrac{3}{8}$
$比\frac{1}{2}大的分數(shù):\dfrac{3}{4},\dfrac{5}{9},\dfrac{6}{7},\dfrac{6}{11},\dfrac{7}{13}$
$故答案為:\dfrac{1}{6},\dfrac{3}{8};\dfrac{3}{4},\dfrac{5}{9},\dfrac{6}{7},\dfrac{6}{11},\dfrac{7}{13}$