解:設(shè)?$A(x_{1},$??$y)、$??$B(x_{2},$??$y)$?
由題意可得?$\begin{cases}{x_{1}+x_{2}=0}\\{x_{2}-x_{1}=1}\end{cases},$?解得?$\begin{cases}{x_{1}=-\dfrac 12}\\{x_{2}=\dfrac 12}\end{cases}$?
?$y=-2×(\frac 12)^2=-\frac 12$?
∴?$A(-\frac 12,$??$-\frac 12)、$??$B(\frac 12,$??$-\frac 12)$?