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電子課本網(wǎng) 第33頁

第33頁

信息發(fā)布者:
解:原式?$=\frac {1}{4} \div(-8) \div(-\frac {1}{8}) \div 1 $?
?$=\frac {1}{4} ×(-\frac {1}{8}) ×(-8) ×1 $?
?$=\frac {1}{4} ×[(-\frac {1}{8}) ×(-8)] $?
?$=\frac {1}{4} ×1 $?
?$=\frac {1}{4}$?

解:因?yàn)?$5^{a}=5,5^=5^{-1},$?所以?$a=1,b=-1.$?
所以?$27^{a}\div 3^{3b}=3^{3a}\div 3^{3b}=3^{3(a-b)}=3^6=729$?
=
=
解?$:(2) $?因?yàn)?$ (\frac {5}{4})^3=\frac {5}{4} ×\frac {5}{4} ×\frac {5}{4}=\frac {125}{64},$?
?$ (\frac {4}{5})^{-3}=\frac {1}{(\frac {4}{5})^3}=\frac {1}{\frac {4}{5}} ×\frac {1}{\frac {4}{5}} ×\frac {1}{\frac {4}{5}}=\frac {5}{4} ×\frac {5}{4} ×\frac {5}{4}= \frac {125}{64} , $?
所以?$ (\frac {5}{4})^3=(\frac {4}{5})^{-3} $?
?$(4) (\frac {7}{5})^{-2}= (\frac {5}{7})^2=\frac {25}{49} $?
解?$:(1)① $?因?yàn)?$ 1^{-2}=1,2^{-1}=\frac {1}{2}, 1> \frac {1}{2} , $?所以?$ 1^{-2}>2^{-1} $?
② 因?yàn)?$ 2^{-3}=\frac {1}{8}, 3^{-2}=\frac {1}{9}, \frac {1}{8}> \frac {1}{9} , $?所以?$ 2^{-3}>3^{-2} $?
③ 因?yàn)?$ 3^{-4}=\frac {1}{81}, 4^{-3}=\frac {1}{64} , \frac {1}{81}<\frac {1}{64} , $?所以?$ 3^{-4}<4^{-3} $?
④因?yàn)?$ 4^{-5}=\frac {1}{1024}, 5^{-4}= \frac {1}{625}, \frac {1}{1024}<\frac {1}{625} , $?所以?$ 4^{-5}<5^{-4} $?
?$\leqslant 2$?
?$>2 $?
解:?$(1) x+1=0 ,$? 且?$ 2 x-5 \neq 0,$??$ x-4 \neq 0 ,$? 解得?$ x= -1 ;$?
?$(2) 2 x-5=x-4 ,$? 解得?$ x=1 ;$?
?$(3) $?當(dāng)指數(shù)是偶數(shù)時(shí),?$ 2 x-5 $?和?$ x-4 $?互為相反數(shù),?$ 2 x-5+x-4=0 ,$? 解得?$ x=3 ,$?
指數(shù)?$ x+1=4 ,$? 符合題意. 
綜上所述,?$ x=-1 $?或?$ x=1 $?或?$ x=3 $?