???$解:(1)DB=12-AD$???
???$所以\frac {AD}{12-AD}=\frac {AE}{EC}=\frac {6}{4}$???
???$所以AD=\frac {36}{5}$???
???$(2)DB=12-\frac {36}{5}=\frac {24}{5},AC=6+4=10$???
???$所以\frac {DB}{AB}=\frac {\frac {24}{5}}{12}=\frac {2}{5}$???
???$\frac {EC}{AC}=\frac {4}{10}=\frac {2}{5}$???
???$所以\frac {DB}{AB}=\frac {EC}{AC}$??
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