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電子課本網(wǎng) 第35頁(yè)

第35頁(yè)

信息發(fā)布者:
???$解:(1)\frac {AB}{BC}=\frac {3}{4},\frac {CF}{CD}=\frac {4-\frac {7}{4}}{3}=\frac {3}{4}$???
???$(2)因?yàn)閈frac {AB}{BC}=\frac {CF}{CD}=\frac {3}{4}$???
???$所以線段AB,BC,CF,CD成比例$???

???$解:(1)DB=12-AD$???
???$所以\frac {AD}{12-AD}=\frac {AE}{EC}=\frac {6}{4}$???
???$所以AD=\frac {36}{5}$???
???$(2)DB=12-\frac {36}{5}=\frac {24}{5},AC=6+4=10$???
???$所以\frac {DB}{AB}=\frac {\frac {24}{5}}{12}=\frac {2}{5}$???
???$\frac {EC}{AC}=\frac {4}{10}=\frac {2}{5}$???
???$所以\frac {DB}{AB}=\frac {EC}{AC}$??

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???$解:設(shè)S_{△COD}= x , S_{△AOE}=y,$???
???$則\frac {35+x}{30}=\frac {OC}{OF}=\frac {y+84}{40}$???
???$即4x- 3y= 112$???
???$\frac {x}{y+84}=\frac {OD}{OA}=\frac {35}{30+40}$???
???$即2x-y= 84$???
???$解得x= 70,y= 56$???
???$所以S_{△ABC}= 40+ 30+ 35+ 70+84+ 56= 315$???